Efficiency of a Carnot engine Thermodynamics Physics Khan

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In the case of an ideal gas, the rate of free expansion is NIL, that is, the work done is 0. The value of 0 is the result regardless of whether the process is irreversible or reversible. For isothermal expansion of an ideal gas, ∆T = 0∴ From ∆U = nCv ∆T∆U = 0 and, from ∆H = nCp ∆tFrom first law of thermodynamics,∆U = Q + Was ∆U = 0 ; Q ≠ 0and W ≠ 0∴Parameters are ∆U = 0; Q ≠ 0; W ≠0and ∆H = 0 Isothermal expansions of a ideal gas is defined as increase in the volume of gas at particular temperature. At particular temperature gas increases entropy. The gas expands in particular temperature as there is increase in entropy. Conclusion: hence the answer is option is (D) none of these.

2020-05-01 · So if the gas expands in the isothermal process, then yes, it will have increased entropy. Additionally, what is entropy calculate the change in entropy of an ideal gas for an isothermal expansion? Change in entropy : ΔS = ∫ i f dS = ∫ i f dQ r /T, where the subscript r denotes a reversible path. An ideal isothermal process must occur very slowly to keep the gas temperature constant.

That is, Boyle's Law. We can calculate the work done by a mole of an ideal gas in a reversible isothermal expansion from volume V 1 to volume V 2 as follows.

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If using a piston cylinder arrangement what we can do is use a spring instead of weights and let the gas reach equilibrium with the spring force(we can use a spring with a desired spring constant). Now add infinitesimally small amount of heat and let the system regain equilibrium. When a fixed amount of ideal gas goes through an isothermal expansion A) its internal (thermal) energy does not change. B) the gas does no work.

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For an ideal gas during an isothermal expansion the enthalpy, as well as internal energy, remains constant.

, so there is no change in the surroundings. Polytropic Compression/Expansion Process.
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For isothermal expansion of an ideal gas

If playback doesn't begin shortly, try 8 Experiment B: Determination of Volumes Ratio Using an Isothermal Process Abstract The objective of this experiment is to determine the ratio of volumes for air in the two vessels by using an isothermal expansion process. This demonstration gives experience with properties of an ideal gas, adiabatic processes, and the first law of thermodynamics. That is, Boyle's Law. We can calculate the work done by a mole of an ideal gas in a reversible isothermal expansion from volume V1 to volume V2 as follows.

The work of expansion for a small change of volume dV against the external pressure P is given by Total work done when the gas expands from initial volume V1 to final volume V2, will be For an ideal gas, PV = nRT i.e.
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Characterizing the before and after states: Before: State 1, , After: State 2, , . , so there is no change in the surroundings. Polytropic Compression/Expansion Process. An ideal isothermal process must occur very slowly to keep the gas temperature constant. An ideal adiabatic process must occur very rapidly without any flow of energy in or out of the system. In practice most expansion and compression processes are somewhere in between, or said to be polytropic. All the reversible isothermal PV work w_(rev) done by an ideal gas to expand was possible by reversibly absorbing heat q_(rev) into the ideal gas.